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SSC GD Previous Paper 18 (Held On: 19 Feb 2019 Shift 1)_English

Option 4 : \(\frac{1}{16}\)

NPCIL Stage-I 2020: Full Mock Test

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**GIVEN:-**

** \(\left[ {\frac{5}{7}\;of\;1\frac{3}{8} - \frac{5}{8}\;of\frac{6}{7}} \right]\; \div \left[ {1 - \frac{1}{7} \times \;\left( {\frac{5}{{12}} + \frac{1}{3}} \right)} \right] \times \frac{{\frac{1}{7} - \frac{1}{9}}}{{\frac{1}{7} + \frac{1}{9}}}\) **

**Concept used**

**Calculation**

** **\(\left[ {\frac{5}{7} \times \frac{{11}}{8} - \frac{5}{8} \times \frac{6}{7}} \right] \div \left[ {1 - \frac{1}{7} \times \;\left( {\frac{9}{{12}}} \right)} \right] \times \frac{{\frac{2}{{63}}}}{{\frac{{16}}{{63}}}}\)

\(\Rightarrow \left[ {\frac{{55}}{{56}} - \frac{{30}}{{56}}} \right] \div \left[ {1 - \frac{3}{{28}}} \right] \times \frac{1}{8}\)

\(\Rightarrow \left[ {\frac{{25}}{{56}} \times \frac{{28}}{{25}}} \right] \times \frac{1}{8} = \frac{1}{2} \times \frac{1}{8} \Rightarrow \frac{1}{{16}}\)