R Error in cut.default : ‘breaks’ are not unique (2 Examples)
In this article, you’ll learn how to handle the “Error in cut.default : ‘breaks’ are not unique” in R.
The content of the page looks like this:
Let’s take a look at some R codes in action…
Creation of Example Data
To start with, let’s create some example data:
x <- 1:10 # Create example vector x # Print example vector # [1] 1 2 3 4 5 6 7 8 9 10 |
x <- 1:10 # Create example vector x # Print example vector # [1] 1 2 3 4 5 6 7 8 9 10
As you can see based on the previous RStudio console output, the example data is a numeric vector ranging from 1 to 10.
Example 1: Reproduce the Error in cut.default : ‘breaks’ are not unique
This example shows how to replicate the “Error in cut.default : ‘breaks’ are not unique” in the R programming language.
Let’s assume that we want to split our vector object by certain breaks using the cut function. Then, we might try to run the following R code:
cut(x, breaks = c(0, 1, 1, 2, 10)) # Reproduce error # Error in cut.default(x, breaks = c(0, 1, 1, 2, 10)) : # 'breaks' are not unique |
cut(x, breaks = c(0, 1, 1, 2, 10)) # Reproduce error # Error in cut.default(x, breaks = c(0, 1, 1, 2, 10)) : # 'breaks' are not unique
Unfortunately, the previous R syntax has returned the “Error in cut.default : ‘breaks’ are not unique”. The reason for this is that we have specified the same break value twice within the cut function (i.e. the break at the value 1).
Example 2: Fix the Error in cut.default : ‘breaks’ are not unique
In Example 2, I’ll show how to avoid the “”Error in cut.default : ‘breaks’ are not unique”.
For this, we simply have to remove all duplicated elements from our vector of breaks:
cut(x, breaks = c(0, 1, 2, 10)) # Resolve error # [1] (0,1] (1,2] (2,10] (2,10] (2,10] (2,10] (2,10] (2,10] (2,10] (2,10] # Levels: (0,1] (1,2] (2,10] |
cut(x, breaks = c(0, 1, 2, 10)) # Resolve error # [1] (0,1] (1,2] (2,10] (2,10] (2,10] (2,10] (2,10] (2,10] (2,10] (2,10] # Levels: (0,1] (1,2] (2,10]
Works fine!
Video & Further Resources
Do you want to learn more about the dealing with the “Error in cut.default : ‘breaks’ are not unique”? Then you may watch the following video on my YouTube channel. I illustrate the examples of this tutorial in the video:
The YouTube video will be added soon.
Furthermore, you may want to have a look at some of the other tutorials on this website. You can find some tutorials on similar topics such as coding errors and lines below:
- Error in as.POSIXlt.character : string not standard unambiguous format
- predict Error in eval(predvars, data, env) : numeric ‘envir’ arg not of length one
- Error in scan: Line 1 did not have X Elements
- Error in read.table: duplicate ‘row.names’ are not allowed
- Solving Error & Warning Messages in R (Example Codes)
- R Programming Language
Summary: In this tutorial, I have demonstrated how to deal with the “Error in cut.default : ‘breaks’ are not unique” in R. Please tell me about it in the comments section, if you have additional questions.